What is the molarity of K+ ions in a 1.25 M solution of K2SO4?
How would I go about solving a problem of this nature? Thank you for all help!
How would I go about solving a problem of this nature? Thank you for all help!
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M= mol/ L
1.25 M K2SO4 = 1.25M K2 = 1.25 mol K2
(1.25mol K2) x (2mol K/ 1mol K2) = 2.5mol K per 1 Liter = 2.5M K
1.25 M K2SO4 = 1.25M K2 = 1.25 mol K2
(1.25mol K2) x (2mol K/ 1mol K2) = 2.5mol K per 1 Liter = 2.5M K