im SOOOO CONFUSED!!!
Could u plz explain it then help me with these?
1. Na+MgF2 -- NaF + Mg
2. Mg + HCl -- MgCl2
3. Cl2 + Kl -- KCl + I2
4. NaCl --Na +Cl2
5. Na + O2 -- Na2O
6. Na + HCl -- H2 + NaCl
7. K + Cl2 -- KCl
Challenge- C2H6 + O2 -- CO2 + H2O
dont worry once i figure out how to do it i will do the rest on my own. there is an entire other side to do!
oh and if you could help with this possible too
atoms are not _____ or _____ duringa chemical reaction scientists know that there muct be the ______number of atoms on each _____of the ________. to balance the chemical equation you must add _______ in front of the chemical formula in th eequation. you cannot drop or change subscripts!
Could u plz explain it then help me with these?
1. Na+MgF2 -- NaF + Mg
2. Mg + HCl -- MgCl2
3. Cl2 + Kl -- KCl + I2
4. NaCl --Na +Cl2
5. Na + O2 -- Na2O
6. Na + HCl -- H2 + NaCl
7. K + Cl2 -- KCl
Challenge- C2H6 + O2 -- CO2 + H2O
dont worry once i figure out how to do it i will do the rest on my own. there is an entire other side to do!
oh and if you could help with this possible too
atoms are not _____ or _____ duringa chemical reaction scientists know that there muct be the ______number of atoms on each _____of the ________. to balance the chemical equation you must add _______ in front of the chemical formula in th eequation. you cannot drop or change subscripts!
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I'm sorry I can't help with the fill-in-the-blanks, but i can balance equations!
The object is to have the same amount of moles of each element on each side. I think of it as a puzzle, and these are simple when you get the hang of it.
1.) First you look for the obvious: on the reactant side flourine has two moles (F2). on the product side there is only one mole of flourine (F). to balance this add a 2 to the compound NaF.
Na+MgF2 => 2NaF + Mg
Then you notice that now you have the same amount of F moles on each side; however, now you have 1 mole of Sodium on the reactant side and two on the product side. You should add a 2 in front of Na.
* 2Na+MgF2 => 2NaF +Mg
Now if you count the moles on each side... 2 Na on each side, 1 Mg on each side, 2 F on each side.
You're completely balanced now so you have your final answer(*).
2.)Is there a hydrogen on the end because you can't balance it if there isn't
Mg+2HCl => MgCl2+2H
3.) Cl2+2KI => 2KCl+I2
4.) 2NaCl => 2Na+Cl2
5.) 4Na+O2 => 2Na2O
6.) 2Na+2HCl => H2+2NaCl
7.) 2K+Cl2 => 2KCl
CHALLENGE:
This one is a little tricky and you can erase and play with the numbers until you get it right.
The object is to have the same amount of moles of each element on each side. I think of it as a puzzle, and these are simple when you get the hang of it.
1.) First you look for the obvious: on the reactant side flourine has two moles (F2). on the product side there is only one mole of flourine (F). to balance this add a 2 to the compound NaF.
Na+MgF2 => 2NaF + Mg
Then you notice that now you have the same amount of F moles on each side; however, now you have 1 mole of Sodium on the reactant side and two on the product side. You should add a 2 in front of Na.
* 2Na+MgF2 => 2NaF +Mg
Now if you count the moles on each side... 2 Na on each side, 1 Mg on each side, 2 F on each side.
You're completely balanced now so you have your final answer(*).
2.)Is there a hydrogen on the end because you can't balance it if there isn't
Mg+2HCl => MgCl2+2H
3.) Cl2+2KI => 2KCl+I2
4.) 2NaCl => 2Na+Cl2
5.) 4Na+O2 => 2Na2O
6.) 2Na+2HCl => H2+2NaCl
7.) 2K+Cl2 => 2KCl
CHALLENGE:
This one is a little tricky and you can erase and play with the numbers until you get it right.
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