2C2H6+O2 => 4CO2+6H2OYou count you Oxygen on the product side (14). YOu can divide 14 by 2 (= 7).FINAL ANSWER:2C2H6+7O2 => 4CO2+6H2OYou have 4 C on each side, 12 H on each side, 14 O on each side :DGood luck in chem. and I hope this helps!......
First you see that you balance the Carbon and Hydrogen.
C2H6+O2 => 2CO2+3H2O
Then you count the oxygen on the product side (7). You notice that their are already 2 Oxygens on the reactant side. You can't evenly divide 7 by two so you go back to the drawing board.
Now you double the C2H6 and rebalace the product side.
2C2H6+O2 => 4CO2+6H2O
You count you Oxygen on the product side (14). YOu can divide 14 by 2 (= 7).
FINAL ANSWER: 2C2H6+7O2 => 4CO2+6H2O
You have 4 C on each side, 12 H on each side, 14 O on each side :D
Good luck in chem. and I hope this helps!
to balance equations, you need to have the same number of atoms of each element on either side of the equation. some are very easy some are quite difficult.
these that you present are on the easy side.
do not change the subscripts of the chemicals
remember, if you put a coefficient in front of a chemical, this alters the entire chemical, not just the element you want to change
remember, coefficients x subscripts = total number of atoms of that element
2Na + MgF2 --> 2NaF + Mg
fill ins:
atoms are not made or destroyed
same
side
equation
coefficients
