I'm given the following equation:
Mn2+(aq) + NaBiO3(s) --> Bi3+(aq) + MnO4-(aq)
I wrote and balanced the half reactions and got:
14 H+ + 2 Mn2+ + 5 NaBiO3 --> 5 Bi3+ + 2 MnO4 + 7 H2O
which is right. However, there another box provided on the right side of the equation for me to add another aqueous product. I don't know what this could possibly be. I tried OH- but it was wrong, and that doesn't make any sense anyways.
What am I missing?
Thank you :)
Mn2+(aq) + NaBiO3(s) --> Bi3+(aq) + MnO4-(aq)
I wrote and balanced the half reactions and got:
14 H+ + 2 Mn2+ + 5 NaBiO3 --> 5 Bi3+ + 2 MnO4 + 7 H2O
which is right. However, there another box provided on the right side of the equation for me to add another aqueous product. I don't know what this could possibly be. I tried OH- but it was wrong, and that doesn't make any sense anyways.
What am I missing?
Thank you :)
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You have no Na+ on the right side and normally you would not include any sodium, but use BiO3- on the left. You also lost the charge on MnO4. Remember, not only do the elements need to balance, but the charges must balance also. They don't the way you have written it.