An ionic compound forms when aluminum reacts with oxygen gas. If a sample of the compound
contains 4.0 * 10^22 aluminum ions and the yield was 100%, how many oxygen molecules reacted
with the aluminum?
the answer is 3 * 10^22 (rounding using sig figs)
but i keep on getting 6 * 10^22. please help!
contains 4.0 * 10^22 aluminum ions and the yield was 100%, how many oxygen molecules reacted
with the aluminum?
the answer is 3 * 10^22 (rounding using sig figs)
but i keep on getting 6 * 10^22. please help!
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Aluminum reacts with oxygen gas to form aluminum oxide. Here's the balanced equation:
4Al + 3O2 ---> 2Al2O3
(4.0 x 10^22 Al ions) * (1 mol Al / 6.022 x 10^23 ions Al) * (3 mol O2 / 4 mol Al)
* (6.022 x 10^23 molecules O2 / 1 mol O2)
= 3 x 10^22 molecules O2 (Answer)
Have a good day.
4Al + 3O2 ---> 2Al2O3
(4.0 x 10^22 Al ions) * (1 mol Al / 6.022 x 10^23 ions Al) * (3 mol O2 / 4 mol Al)
* (6.022 x 10^23 molecules O2 / 1 mol O2)
= 3 x 10^22 molecules O2 (Answer)
Have a good day.