3(logx-2log2)
I got log (x^3/64). Tell me what you get. :)
I got log (x^3/64). Tell me what you get. :)
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Use those log properties:
nlog(x) = log(xⁿ)
log(x) - log(y) = log(x/y)
That gives us:
log(x³) - 2log(2³)
= log(x³) - 2log(8)
= log(x³) - log(8²)
= log(x³) - log(64)
= log(x³/64)
I hope this helps!
nlog(x) = log(xⁿ)
log(x) - log(y) = log(x/y)
That gives us:
log(x³) - 2log(2³)
= log(x³) - 2log(8)
= log(x³) - log(8²)
= log(x³) - log(64)
= log(x³/64)
I hope this helps!