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m w's solution is just fine, there is no mistake. The fact that the final temperature is 22 C only serves to help us determine that the water changes 13 C (this is the reason for 35 minus 22). The division comes about as you do the algebra to solve for m.
In addition, Ian Tonner says:
"You might be wondering why I used .00418 instead of 4.18."
I would point out that m w's solution provides for consistency of units. If you look here:
(50g) x (2.4 kJ/g) x (1000J/1kJ)
you will see that the third term converts from kJ to J.
If you want to see problems of this ilk, I have several (maybe none of this exact type) here:
http://www.chemteam.info/Thermochem/Ther…
In addition, Ian Tonner says:
"You might be wondering why I used .00418 instead of 4.18."
I would point out that m w's solution provides for consistency of units. If you look here:
(50g) x (2.4 kJ/g) x (1000J/1kJ)
you will see that the third term converts from kJ to J.
If you want to see problems of this ilk, I have several (maybe none of this exact type) here:
http://www.chemteam.info/Thermochem/Ther…
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heat gained by water evaporating = heat lost by water cooling
m dHvap = m Cp dT
(50g) x (2.4 kJ/g) x (1000J/1kJ) = m x (4.184 J/g°C) x (35°C - 22°C)
solve for m
m dHvap = m Cp dT
(50g) x (2.4 kJ/g) x (1000J/1kJ) = m x (4.184 J/g°C) x (35°C - 22°C)
solve for m