"Sodium metal reacts with water in the following single-displacement reaction: 2 Na(s) + 2 H20 -> 2Na0H (aq) + H2(g) Determine the limiting reactant and mass of H2 gas produced when 2.0 g of Na is added to 10.0 g H20."
The first part I already know how to do, I found that it makes .087 moles of H20 and .555 moles of Na, so H20 is the limiting reactant. I also know that in this problem the conservation of mass law applies, so the mass of the reactants should equal the products,so 2NaOH and H2 combined should equal 14.37 g. How do I know how much each substance weighs?
The first part I already know how to do, I found that it makes .087 moles of H20 and .555 moles of Na, so H20 is the limiting reactant. I also know that in this problem the conservation of mass law applies, so the mass of the reactants should equal the products,so 2NaOH and H2 combined should equal 14.37 g. How do I know how much each substance weighs?
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So if H20 is limiting you are going to have half as many moles of hydrogen as you do water. (2:1 ratio in the balanced equation).
So you will have 0.0435 moles of hydrogen. Just calculate the weight now.
You appear to be going beyond the scope of the question. If you wanted to find the weight of everything after the reaction, you will also need to take into account unreacted starting materials.
So you will have 0.0435 moles of hydrogen. Just calculate the weight now.
You appear to be going beyond the scope of the question. If you wanted to find the weight of everything after the reaction, you will also need to take into account unreacted starting materials.