Any1 know how to do chemistry

You make yourself some hot tea (225 mL of tea at 88*C), but after making it you discover that you are really in the mood for iced tea. You have an unlimited supply of ice cubes at 0*C. What mass of ice cubes will you need to add in order to cool your tea to 0*C and get the iced tea you crave?

Density of your ice tea= 1.00g/mL (same was water)
Specific heat of your tea = 4.184 J/*C g (same as water)
Specific heat of ice = 2.087 J/*C g
Heat of fusion = 6.02 kJ/mol
Heat of Vaporization = 40.7 kJ/mol

Solve and explain Please & Thank You

to my understanding of the question, we have hot tea ( liquid ) and we are going make it 'ice tea' where the tea is still liquid. therefore the system will not change in state

however certain ice will become liquid when they are mixed up. ( buerk dilute tea lol)
so the ice will become liquid ice and remain at zero degrees cel

so for tea : Q = mc(t1 - t2) ............ q ( thermal energy)

ice : Q = nHf

since thermal e will be same for both( same system)

mc (t1 - t2) = n Hf i presume tea is also 1.00 g/ml
D = m/v
M = 1x 225 = 225 g
225 x 4.184 ( 88 - 0 ) = n 6.02 x10^3
N = 13.76 MOLES

so now m/m.r = N

m = n x m.r (18 for h20)
= 247.5 g