A. 20;2
B. 40;2
C. 20;4
D. 10;4
E. 10;2
B. 40;2
C. 20;4
D. 10;4
E. 10;2
-
D. 10;4
Meiosis produces 4 haploid daugther cells, each wih half the number of chromosomes as the diploid parent cell.
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Edited to Add:
Okay, some bad information was given by others, so I'll have to spend time to explain it right so that no one is misinformed.
The cell before meiosis is diploid (2n): that means it has two complete sets of chromosomes, one from the mother and one from the father.
This parent cell has 20 chromosomes; since it has 2 sets of chromosomes, it has 2 sets of 10 chromosomes each. Thus, n = 10 and 2n = 20.
In S phase of interphase, DNA replication occurs, and each chromosome is duplicated -- but, the two identical copies remain joined together (they are called sister chromatids later). So while DNA replication doubles the amount of DNA in the cell, it does not change the number of chromosomes.
So the parent cell had 20 chromosomes, each with 1 DNA molecule; but after DNA replication in S phase the cell has 20 chromosomes each with 2 DNA molecules (sister chromatids).
In meiosis I, the chromosomes separate and move to opposite poles and then cytokinesis divides the cell in two. There are now 2 cells, each with hald of the parent cells chromosomes. So each of the two cells has 10 chromosomes, with each chromosome consisting of two sister chromatids. At this point, the cells are already considered to be haploid (since they have half the number of chromosomes as the parent cell).
In meiosis II, each of the 2 daugther cells divides again. For each cell, the 2 sister chromatids of the 10 chromosomes separate and move to opposite poles. After cytokinesis, that one daugther cell produced 2 daugther cells, each with 10 chromosomes, with each chromosome having only 1 DNA molecule. Since that is for only 1 of the two daugther cells from meiosis I, the total is 4 haploid daugther cells, each with 10 chromosomes, with each chromosome having only 1 DNA molecule.
Meiosis produces 4 haploid daugther cells, each wih half the number of chromosomes as the diploid parent cell.
---------------------------------------
Edited to Add:
Okay, some bad information was given by others, so I'll have to spend time to explain it right so that no one is misinformed.
The cell before meiosis is diploid (2n): that means it has two complete sets of chromosomes, one from the mother and one from the father.
This parent cell has 20 chromosomes; since it has 2 sets of chromosomes, it has 2 sets of 10 chromosomes each. Thus, n = 10 and 2n = 20.
In S phase of interphase, DNA replication occurs, and each chromosome is duplicated -- but, the two identical copies remain joined together (they are called sister chromatids later). So while DNA replication doubles the amount of DNA in the cell, it does not change the number of chromosomes.
So the parent cell had 20 chromosomes, each with 1 DNA molecule; but after DNA replication in S phase the cell has 20 chromosomes each with 2 DNA molecules (sister chromatids).
In meiosis I, the chromosomes separate and move to opposite poles and then cytokinesis divides the cell in two. There are now 2 cells, each with hald of the parent cells chromosomes. So each of the two cells has 10 chromosomes, with each chromosome consisting of two sister chromatids. At this point, the cells are already considered to be haploid (since they have half the number of chromosomes as the parent cell).
In meiosis II, each of the 2 daugther cells divides again. For each cell, the 2 sister chromatids of the 10 chromosomes separate and move to opposite poles. After cytokinesis, that one daugther cell produced 2 daugther cells, each with 10 chromosomes, with each chromosome having only 1 DNA molecule. Since that is for only 1 of the two daugther cells from meiosis I, the total is 4 haploid daugther cells, each with 10 chromosomes, with each chromosome having only 1 DNA molecule.
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