I'm really confused right now.
1.In Guinea pigs the allele for shot hair (H) is dominant over the allele for long hair (h) and the allele for black hair (B) is dominant over the allele for brown hair (b).
For this punnet square, I got hb on the left side and HB on the top.
Genotypic ratio, I got 16/16 HhBb hetorozygous short and hetorozygous black.
Phenotypic ratio:16/16 short black hair
Here's the part I don't get:
If 2 individuals of the F1 generation are crossed, what are the possible genotypes and what is their expected ratio?
1.In Guinea pigs the allele for shot hair (H) is dominant over the allele for long hair (h) and the allele for black hair (B) is dominant over the allele for brown hair (b).
For this punnet square, I got hb on the left side and HB on the top.
Genotypic ratio, I got 16/16 HhBb hetorozygous short and hetorozygous black.
Phenotypic ratio:16/16 short black hair
Here's the part I don't get:
If 2 individuals of the F1 generation are crossed, what are the possible genotypes and what is their expected ratio?
-
That would mean you would use two of the pigs from the generation one, which are HhBb and cross them. The possible alleles that the g. pigs could give in a gamete are as follows HB, Hb, hB, hb. both of them could give any of these four combinations so now all you do is make these four into the top and side of a 4x4 punnet square. this means that the 16 possible future generations are 1HHBB 1HHBb 2HHbb 3HhBB 4HhBb 3Hhbb 2hhBB 1hhBb 1hhbb