How many moles of H2O are produced when 6 mol of O2 is consumed in burning methyl alcohol, CH3OH, according to the following equation?
2CH3OH + 3O2 ----> 2CO2 + 4H2O
12 moles of H2O are produced.
2CH3OH + 3O2 ----> 2CO2 + 4H2O
12 moles of H2O are produced.
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You are incorrect.
For every 3 moles of O2 consumed, 4 moles of H2O are produced.
So if you had 6 moles of O2...
(6 moles O2/ 3 moles O2) x 4 moles H2O = 8 moles H2O produced
For every 3 moles of O2 consumed, 4 moles of H2O are produced.
So if you had 6 moles of O2...
(6 moles O2/ 3 moles O2) x 4 moles H2O = 8 moles H2O produced
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2CH3OH + 3O2 ----> 2CO2 + 4H2O
The coefficients, in the balanced equation, indicate the mole ratio of products and reactants.
According to the equation above, 2 moles of CH3OH react with 3 moles of O2 to produce 2 moles of CO2 and 4 moles of H2O.
H2O / O2 = 4 / 3
x /6 = 4 /3
x = 6 * 4/3 = 8 moles of H2O
The coefficients, in the balanced equation, indicate the mole ratio of products and reactants.
According to the equation above, 2 moles of CH3OH react with 3 moles of O2 to produce 2 moles of CO2 and 4 moles of H2O.
H2O / O2 = 4 / 3
x /6 = 4 /3
x = 6 * 4/3 = 8 moles of H2O