You are able to exert a force of 300 Newtons on the piston of a hydraulic lift. The piston as an area of 64 cm^2, What would the area of the other plunger have to be if you wanted to lift a load of 200 Newtons?
-
(200/300) x 64 = 42.67cm^2.
The harder way:
(300/64) = force of 4.6875 N. per cm^2.
(200/4.6875) = 42.67cm^2.
The harder way:
(300/64) = force of 4.6875 N. per cm^2.
(200/4.6875) = 42.67cm^2.
-
LUIGI3033!!!!! Whatever is ur name!!!! at least you must have courtesy to bother about someone's effort!!!
By the way, in true sense you were STUPID asking such simple questions because it did not at all fit enough to get into your mind!!!!
By the way, in true sense you were STUPID asking such simple questions because it did not at all fit enough to get into your mind!!!!
Report Abuse
-
Here,
pressure = Force / Area
Therefore, the force exerted on the piston of hydraulic = 300 N
having area = 64 cm^2 = 64 x 10^-4 m^2
Pressure on he other plunger = 300 N / 64 x 10^-4 m^2 = 46875 N/m^2 = 46875 pa
Given, the force to be lifted by the plunger = 200 N
and pressure availed or the applied pressure to the plunger = 46875 pa
Again, pressure = force / area
Area = force / pressure = 200 N / 46875 pa
= 200 N /46875 N/m^2
= 0.00426 m^2
= 0.00426 m^2 * 10000
= 42.6 cm^2
Thus, the area required to lift the load is 42.6 cm^2
Pascal's Law:
In a closed liquid (inside a vessel) the pressure applied at any part is equally transmitted in all directions and in the same amount.
Here, in the hydraulic we exerted or applied the pressure of 46875 pa. The hydraulic pistons are closed inside a liquid vessel or container. Therefore, according to the pascal's law the pressure got equally distributed and helped the plunger to lift the load up to the surface at the same time.
GOOD LUCK :)
pressure = Force / Area
Therefore, the force exerted on the piston of hydraulic = 300 N
having area = 64 cm^2 = 64 x 10^-4 m^2
Pressure on he other plunger = 300 N / 64 x 10^-4 m^2 = 46875 N/m^2 = 46875 pa
Given, the force to be lifted by the plunger = 200 N
and pressure availed or the applied pressure to the plunger = 46875 pa
Again, pressure = force / area
Area = force / pressure = 200 N / 46875 pa
= 200 N /46875 N/m^2
= 0.00426 m^2
= 0.00426 m^2 * 10000
= 42.6 cm^2
Thus, the area required to lift the load is 42.6 cm^2
Pascal's Law:
In a closed liquid (inside a vessel) the pressure applied at any part is equally transmitted in all directions and in the same amount.
Here, in the hydraulic we exerted or applied the pressure of 46875 pa. The hydraulic pistons are closed inside a liquid vessel or container. Therefore, according to the pascal's law the pressure got equally distributed and helped the plunger to lift the load up to the surface at the same time.
GOOD LUCK :)