If you could help with this at all, that would be great!
The distance traveled by a dropped object (ignoring air resistance) equals 1/2gt^2, where g is the acceleration of the object due to gravity and t is the time since it was dropped. If acceleration due to gravity is about 10 m/s, how much time does it take an object to fall 80 meters?
Thanks!
The distance traveled by a dropped object (ignoring air resistance) equals 1/2gt^2, where g is the acceleration of the object due to gravity and t is the time since it was dropped. If acceleration due to gravity is about 10 m/s, how much time does it take an object to fall 80 meters?
Thanks!
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s = 1/2 g t^2
2s = gt ^2
2s/g = t^2
sqrt( 2s/g) = t
so now just plug in the numbers
sqrt( 2 * 80 / 10) = sqrt(16) = 4 s
2s = gt ^2
2s/g = t^2
sqrt( 2s/g) = t
so now just plug in the numbers
sqrt( 2 * 80 / 10) = sqrt(16) = 4 s
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80 = (1/2)gt^2
80 = 0.5 x 10 x t^2
t^2=16
t = 4s
80 = 0.5 x 10 x t^2
t^2=16
t = 4s
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Rearrange for time.
T = sqrt.(2h/g) = 4 secs.
T = sqrt.(2h/g) = 4 secs.