How much heat must be added to 8 kg of water to change it into steam at 120 degrees celsius

What is the initial temp of the water? The total heat would be m x Cp1 x delta T1 + m x Hf + m x Cp2 x Delta T2

The initial temp = t1, so delta T1 would be 100 -t1

Cp1 = heat capacity of water

Cp2 = heat capacity of steam

delta T2 = 120 -100 = 20 degrees C

what is the second m stand for and what does Hf stand for. btw the initial temp is 25 degrees C

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