If a 1500 car can accelerate from 30 to 50 in 3.5 , how long will it take to accelerate from 50 to 70 ? Assume the power stays the same, and neglect frictional losses.
THANKYOU!
THANKYOU!
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Although there are no units, ratios do not require units.
power = gain in energy / time
and energy is proportional to the square of the speeds.
time is then proportional to energy / power but other factors are constant
so time is proportional to the gain in v^2
hence T2/T1 = ( 70^2-50^2) / (50^2-30^2)
=1.5
i.e it takes 1.5 times longer in the second case ( 5.25 unspecified units)
And this would be true whether the distances were in leagues and the times in minutes,
or if the distances were in cm and the time in milliseconds.
power = gain in energy / time
and energy is proportional to the square of the speeds.
time is then proportional to energy / power but other factors are constant
so time is proportional to the gain in v^2
hence T2/T1 = ( 70^2-50^2) / (50^2-30^2)
=1.5
i.e it takes 1.5 times longer in the second case ( 5.25 unspecified units)
And this would be true whether the distances were in leagues and the times in minutes,
or if the distances were in cm and the time in milliseconds.
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No units.
No answer.
No answer.