calculate the centripetal acceleration of an object at the equator due to rotation of earth. the radius of earth is 6.4x10^6m.
please help me to answer this question . tq .
please help me to answer this question . tq .
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To compute the centripetal acceleration, a = v²/r we must first compute the circumference:
C = 2πr and v = (C/24 hr)(1 hr/3600 s)
a = 4π²(6.4 × 10^6 m)/{24²(3600s)²}
a = 0.034 m/s²
C = 2πr and v = (C/24 hr)(1 hr/3600 s)
a = 4π²(6.4 × 10^6 m)/{24²(3600s)²}
a = 0.034 m/s²