Physics Question: free fall equation
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Physics Question: free fall equation

[From: ] [author: ] [Date: 12-07-01] [Hit: ]
..c) g acting downwards!f) 14.......
A ball is ejected directly upward at 60 m/sec from the edge of a 100 m cliff.

a) what is the velocity and the position of the ball at t=4 sec? At t=9 sec?
b) when does the ball reach the highest point?
c) when is the acceleration at the highest point?
d) what is the maximum height that the ball can reach?
e) what is the speed of the ball when it passes the edge of the cliff on the way down?
f) when does the ball come back to the ground?
g) what is the impact velocity of the ball?

-
a) At t=4... 160m above the cliff
At t=9... 135m above the cliff

b) At t=6s

c) g acting downwards!

d) 180m above the cliff

e) 60 m/s

f) 14.82 seconds

g) 74 m/s

-
V = Vi -g*t
Y = Vi*t - ½g*t²

Ymax @ t = Vi/g

a = -g at all times

Hmax = Vi²/2g

S2 = Si = 60 m/s

-100 = Vi*t - ½g*t² (solve for t)

Vimp = √[Vi² + 2g(100)]
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