Three masses are arranged in the (x, y) 3kg (0,0) 6kg(0,3) 7kg (7,0) What is the magnitude of the resulting fo

Three masses are arranged in the (x, y)
3kg (0,0)
6kg(0,3)
7kg (7,0)
What is the magnitude of the resulting
force on the 3 kg mass at the origin? The
value of the universal gravitational constant
is 6.6726 × 10−11 N · m2/kg2 .
Answer in units of N

force 1 from the mass (0.3)
F1 = GMm/R^2
F1 = 6.67*10^-11*3*6/9 = 1.334*10^-10 N

force 2 from mass (7, 0)
F2 = 6.67*10^-11*3*7/49 = 2.858*10^-11 N

total force using Pythagoras theorem:
F = √((1.334*10^-10)^2 + (2.858*10^-11)^2)
F = 1.3643*10^-10 N <--- ans.


OG