I need help solving this problem, which equations would i use to solve it and what steps taken to get to the solution.
A 5 kg mass rests on a frictionless, horizontal, wooden table top, and is attached to one end of a spring anchored at its other end. If the spring has a spring constant = 12 N/cm and the mass is pulled back (in the positive direction) 20 cm and released, what is the Kinetic energy at x= 3.7
A 5 kg mass rests on a frictionless, horizontal, wooden table top, and is attached to one end of a spring anchored at its other end. If the spring has a spring constant = 12 N/cm and the mass is pulled back (in the positive direction) 20 cm and released, what is the Kinetic energy at x= 3.7
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E = F*d = ((kx)*x)/2 (potential energy of spring) = 1/2 mv^2 (kinetic energy of mass)