Physics 250: Torque at pivot point
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Physics 250: Torque at pivot point

[From: ] [author: ] [Date: 12-04-10] [Hit: ]
The see-saw is 2.8 m long, weighs 11 N and is tilted at an angle of 20◦ from the horizontal. The center of mass of the see-saw is half way along its length, and lies right above the pivot.Part 1: What torque does the rope exert about the pivot point?......
Can't seem to get the correct answer for either of these when I try and submit them for my online homework. Can anyone help me and show work, please?

A child weighing 37 N climbs onto the right end of a see-saw, little knowing that it is tied down with a rope at its left end. The see-saw is 2.8 m long, weighs 11 N and is tilted at an angle of 20◦ from the horizontal. The center of mass of the see-saw is half way along its length, and lies right above the pivot.

Part 1: What torque does the rope exert about the pivot point? Take counter-clockwise to be positive.
Answer in units of N · m

Part 2: What force does the rope exert downwards on the see-saw? Give a positive answer.
Answer in units of N

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Assuming the rope is vertical,

1. Q = Wc*D = 37*(2.8/2)*cos20° = 48.68 N∙m

2. F = W = 37 N
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