A rectangular wooded block measures 10.0 cm length, 4.00 cm wide, and 2.00 cm
height. When the block is placed in water, it floats horizontally, with its bottom face
1.65 cm below the surface. What is the density of the wood?
The answer is 0.825 g/cm^3, but I can't figure out how to get that. Show steps to I can try to understand. Thanks.
height. When the block is placed in water, it floats horizontally, with its bottom face
1.65 cm below the surface. What is the density of the wood?
The answer is 0.825 g/cm^3, but I can't figure out how to get that. Show steps to I can try to understand. Thanks.
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According to Archimedes’ principle, the block will displace a mass of water equal to its own mass. The mass of water displaced is:
ρ = m/V
m = ρV
= (1.00g/cm³)(10.0cm x 4.00cm x 1.65cm)
= 66.0g
Since this is also the mass of the wood block, then its density is:
ρ = 66.0g / (10.0cm x 4.00cm x 2.00cm)
= 0.825g/cm³
Hope this helps.
ρ = m/V
m = ρV
= (1.00g/cm³)(10.0cm x 4.00cm x 1.65cm)
= 66.0g
Since this is also the mass of the wood block, then its density is:
ρ = 66.0g / (10.0cm x 4.00cm x 2.00cm)
= 0.825g/cm³
Hope this helps.