The maximum value of current in a coil of inductance 2H when the supply is of 314V at 50 Hz is

The maximum value of current in a coil of inductance 2H when the supply is of 314V at 50 Hz is

E = 314 V = 100 π
X =( 2 π *50*2 )

I = E /X = 100 / 200 = 0.5 A
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Inductance, L = 2 H
Applied Voltage, V = 314 V
Frequency, f = 50 Hz.
Inductive Reactance = XL
Current = I

XL = 2π f L
XL = 2π(50)(2)
XL = 200π
XL = 628.32 Ω

I = V / XL
I = 314 / 628.32
I = 0.4997

The current is about a half an amp.
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