A fish looking up through water sees the outside world, contained in a circular horizon. If the refractive index of water is 4/3 ,and the fish is 12 cm below the water surface, the radius of this circle in cm is :-
(a) 36(√7)
(b) 36 / √7
(c) 36(√5)
(d) 4√5
(a) 36(√7)
(b) 36 / √7
(c) 36(√5)
(d) 4√5
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the radius of the circle is r= h / square root of (u^2 - 1), where 'h' is the depth and 'u' is the refractive index.
hence, r= 12 / square root of ( 16/9 - 1) = 36 / square root of (7). so the correct answer is (b)
hence, r= 12 / square root of ( 16/9 - 1) = 36 / square root of (7). so the correct answer is (b)