A projectile is fired straight upward from the ground.
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A projectile is fired straight upward from the ground.

[From: ] [author: ] [Date: 12-03-20] [Hit: ]
Find the maximum height of the projectile. I think i know how to do it but i am not sure if i did it right.-Take the derivative of the equation and set it equal to zero. This will tell you when the slope of the line is zero (the vertex).You should get -32x + 96= 0 for the derivative.So the maximum height is 144 ft.......
A projectile is fired straight upward from the ground. Its height h in feet after t seconds is given by the equation h(t)=-16t^2+96t. Find the maximum height of the projectile. I think i know how to do it but i am not sure if i did it right.

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Take the derivative of the equation and set it equal to zero. This will tell you when the slope of the line is zero (the vertex).

You should get -32x + 96= 0 for the derivative. Solve for x and you get x=3

Plug this back into your original equation to find the y value (the height)

-16(3)^2 + 96(3)= 144

So the maximum height is 144 ft.
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