(c) 3.33 g NaOH in 0.895 L H2O

can you help me find the mole fraction of ^^^^ (:

Before we solve this problem we need to recall the formula for mole fraction.

MOLE FRACTION = # of moles in a substance / total # of moles in the solution.

First lets find out how many moles are in 3.33g of NaOH.

3.33g NaOH x (1 mol NaOH / 40g NaOH) = .08325 mol NaOH

Now lets find out how many grams of H2O we have.

895mL H2o x (1g H2O / mL) = 895g of H2O ----> *remember density of H2O 1g/mL

Now lets find how many moles of H2O

895g H2O x (1 mol H2O / 18g H2O) = 49.72 mol H2O

MOLE FRACTION = .08325 / (.08325) + (49.72) =


THE FINAL ANSWER IS = .00167