A 1.3 m length of wire carrying 7.5 A of current is oriented horizontally. At that point on the Earth's surface, the dip angle of the Earth's magnetic field makes an angle of 40° to the wire. Estimate the magnetic force on the wire due to the Earth's magnetic field of 5.5 x 10^-5 T at this point.
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Hello friend Crafty, let us the formula F = B i L sin@
Here B is the magnetic field induction due to earth's mag field ie 5.5 x 10^-5 T
The current i = 7.5 A
L = 1.3 m
and @ - the angle between the magnetic field induction vector and the direction of current ie 40 deg
Hence F = 5.5*10^-5*7.5*1.3*Sin 40 = 3.44*10^-4 N
Here B is the magnetic field induction due to earth's mag field ie 5.5 x 10^-5 T
The current i = 7.5 A
L = 1.3 m
and @ - the angle between the magnetic field induction vector and the direction of current ie 40 deg
Hence F = 5.5*10^-5*7.5*1.3*Sin 40 = 3.44*10^-4 N
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force on the wire is F = B i l sin(theta) = 5.5 x10^-5 x 7.5 x 1.3 x sin(40)
= 5.5x10^-5 x 7.5 x1.3 x0.6428 = 3.45 x10^-4 N.
= 5.5x10^-5 x 7.5 x1.3 x0.6428 = 3.45 x10^-4 N.