A photo electric surface has a work function of 4eV.What is the maximum velocity of the photo electrons emitted by light of frequency 10^15 Hz incident on the surface ?
-
h n - φ = 0.5mv²
6.6e-34*1e15 – 6.4e-19= 0.5*9e-31 v²
2.e-20 = 4.5e-31 v²
v = 2.108e5 m/s
=====================
6.6e-34*1e15 – 6.4e-19= 0.5*9e-31 v²
2.e-20 = 4.5e-31 v²
v = 2.108e5 m/s
=====================