A child goes down a playground slide that is inclined at an angle of 24.0° below the horizontal. Find the acceleration of the child given that the coefficient of kinetic friction between the child and the slide is 0.425.
Answer in m/s2
Answer in m/s2
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Newton’s 2nd law for the forces acting on the child parallel to the slide (take down as positive):
ΣF(x) = ma = mgsinθ – μmgcosθ
a = g(sinθ – μcosθ)
= 9.81m/s²(sin24.0° - 0.425cos24.0°
= 0.181m/s²
Hope this helps.
ΣF(x) = ma = mgsinθ – μmgcosθ
a = g(sinθ – μcosθ)
= 9.81m/s²(sin24.0° - 0.425cos24.0°
= 0.181m/s²
Hope this helps.