V^2 = 2gh
so h = v^2/(2g) =7.2^2 /(2 * 9.8)
F= k q1 q2 / r^2
F = ma
ma = k q1 q2 / r^2
q1 = ma * r^2 /(kq2) Now just substitute your values.
F = bqv where v is the component of the velocity perpendicular to the magnetic field.
= b q v * cos ( theta) theta being the angle between them.
The angle is 180 - 43 - 38 = 99 degrees.
You can substitute and calculate from this.
Pelumi has two choices. If he zooms AROUND at 0.6c there is no relative velocity so he is wasting his time.
If he moves AWAY at 0.6c he will be a long way from the exam centre when it comes time to do the exams so he will fail.
His better choice would have been to study assiduously during term time. And be full of confidence and capability.
Instead of rushing around in a spaceship he could spend the night before the exam with some friends just chilling out and putting himself into a good relaxed frame of mind so he will do his best work the next day on the exam.