A child slides down a slide at a 52 degree angle with a coefficient of friction of .15 and a length of 5.2 meters. The mass of the child is 39.7 kg and their initial velocity is 0.71 m/s.
I found Force Weight to be 389.06 N, Normal Force is 239.52 N, and Frictional Force is 35.92 N.
How do I find the acceleration of the child and the final velocity of the child at the end of the slide? Please explain? thanks!
I found Force Weight to be 389.06 N, Normal Force is 239.52 N, and Frictional Force is 35.92 N.
How do I find the acceleration of the child and the final velocity of the child at the end of the slide? Please explain? thanks!
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m * g * sin(angle) is the component of gravity acting parallel to an incline, m * g * cos(angle) is the
component of gravity acting perpendicular to an incline (equal to the normal force in most cases) so
acceleration would be (g * sin(52)) - (g * coefficient of friction * cos(52)) = 6.82 ms^-2
Once you find the acceleration, use this formula:
final velocity ^ 2 = initial velocity ^ 2 - 2a(displacement)
final velocity = sqrt(initial velocity ^ 2 - 2a(displacement)) = 8.45 m/s
component of gravity acting perpendicular to an incline (equal to the normal force in most cases) so
acceleration would be (g * sin(52)) - (g * coefficient of friction * cos(52)) = 6.82 ms^-2
Once you find the acceleration, use this formula:
final velocity ^ 2 = initial velocity ^ 2 - 2a(displacement)
final velocity = sqrt(initial velocity ^ 2 - 2a(displacement)) = 8.45 m/s