A worker pushing a 35.0-kg wooden crate at a constant speed for 13.1 m

along a wood floor does 320 J of work applying a constant horizontal force of magnitude F0 on the crate.

(a) Determine the value of F0. (N)

(b) If the worker now applies a force greater than F0, describe the subsequent motion of the crate.

(c) Describe what would happen to the crate if the applied force is less than F0.

energy = force * displacement

NewtonMeters = Newtons * Meters
320 =( x )(13.1)

x = 320/13.1 = 24.43 N

(b) Because the velocity is constant, the force of friction must equal F0.
a greater force would accelerate the crate.

(c) a smaller force would allow the force of friction to decelerate the crate.