A 60-kg pole vaulter running at 11 m/s vaults over the bar. Her speed when she is above the bar is 1.0 m/s.

Neglect air resistance, as well as any energy absorbed by the pole, and determine her altitude as she crosses the bar. (m)

at the start, all her energy is in KE, at the top, she has both KE and PE, using conservation of energy

KE at start = PE at top + KE at top

1/2 x 60kg x (11m/s)^2 = 60kg x 9.8m/s/s x h + 1/2 x 60kg x (1m/s)^2

3600J = 60kg x 9.8m/s/s x h

h = 6.12m

Use conservation of energy.

Calculate the change in kinetic energy between the vaulter on the ground and in the air.
That energy is converted to gravitational potential energy.
Calculate the change in height that would produce this much potential energy.

Starting Kinetic Energy = 1/2x60x11^2

Kinetic Energy at Max Height = 1/2x60x1^2

Calculate change in KE which is equal to gain in Gravitational Potential Energy (GPE)

GPE = m.g.h = 60x9.81xh

Find h