The block of mass 2.30044 kg has an acceleration of 3.1 m/s^2 as shown.
the diagram looks like this:
<--a----2.30044kg<---- (magnitude F which is 22 degrees above horizontal)
assume gravity is 9.8 and surface is frictionless
the diagram looks like this:
<--a----2.30044kg<---- (magnitude F which is 22 degrees above horizontal)
assume gravity is 9.8 and surface is frictionless
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I have to assume you want the accelerating force, or applied force? I'll assume the latter.
Force = (mass x acceleration), = 2.30044 x 3.1, = 7.131364N. horizontal component.
7.13136/(cos 22) = 7.69129N. at 22 degrees.
Force = (mass x acceleration), = 2.30044 x 3.1, = 7.131364N. horizontal component.
7.13136/(cos 22) = 7.69129N. at 22 degrees.