A. y=2x+2
y=x^2+4x-5
B. 3y=x^2-40
x+2y= -6
y=x^2+4x-5
B. 3y=x^2-40
x+2y= -6
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just equate the y's, since y=y
y=2x+2 ----- 1
y=x^2 + 4x -5 -------- 2
eq. 1= eq. 2
2x+2=x^2+4x-5
0=x^2 + 2x - 7 i transposed the terms on the left side to the right side
then solve it by using the quadratic equation...
x=1.83 or x= -3.83
then subst. this values to eq.1 or 2 to get the y value...
for letter B. isolate the y's first then equate them again
3y=x^2-40
y=(x^2-40)/3 ------- eq. 1
x+2y=-6
y=( -x - 6)/2 ------- eq. 2
then equate them again
(x^2-40)/3=(-x - 6)/2
2x^2-80=-3x - 18
2x^2 + 3x - 62 = 0
x=4.87 ; x= -6.37 then subst. it aqain to eq 1 or 2 to get the y coordinate... :)
y=2x+2 ----- 1
y=x^2 + 4x -5 -------- 2
eq. 1= eq. 2
2x+2=x^2+4x-5
0=x^2 + 2x - 7 i transposed the terms on the left side to the right side
then solve it by using the quadratic equation...
x=1.83 or x= -3.83
then subst. this values to eq.1 or 2 to get the y value...
for letter B. isolate the y's first then equate them again
3y=x^2-40
y=(x^2-40)/3 ------- eq. 1
x+2y=-6
y=( -x - 6)/2 ------- eq. 2
then equate them again
(x^2-40)/3=(-x - 6)/2
2x^2-80=-3x - 18
2x^2 + 3x - 62 = 0
x=4.87 ; x= -6.37 then subst. it aqain to eq 1 or 2 to get the y coordinate... :)
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you have to put both of the equations equal to each other.
a) 2x+2=x^2=4x-5 and work the equation all the way down...remember to have the X all in in one side in order to find the answer.
do the same on problem B.
a) 2x+2=x^2=4x-5 and work the equation all the way down...remember to have the X all in in one side in order to find the answer.
do the same on problem B.
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2x+2=x^2+4x-5
you can check your solutions here
http://www.wolframalpha.com/input/?i=2x%…
you can check your solutions here
http://www.wolframalpha.com/input/?i=2x%…