What is the minimum force

The weight of the block in the drawing is 60.2 N. The coefficient of static friction between the block and the vertical wall is 0.600. Please regard the 40o angle between F and the vertical in the picture below as a 3-significant figure number. It the picture shows a block on a wall with an arm pushing upward at a 40 degree angle.


(a) What minimum force F is required to prevent the block from sliding down the wall? (Hint: The static frictional force exerted on the block is directed upward, parallel to the wall.)
Your answer was incorrect, but has changed from what was graded. N
(b) What minimum force is required to start the block moving up the wall? (Hint: The static frictional force is now directed down the wall.

The component of F pushing the block against the wall is Fsin40. Fsin40 * 0.6 is the friction force impeding the block from moving up or down.
When holding the block stationary, the friction force subtracts from the weight
60.2-F*sin40*0.6=Fcos40 => F = 60.2/(cos40+0.6sin40) = 52.270N To hold the block stationary
When pushing up, the friction force adds to the weight
The vertical component of F pushing up on the block is Fcos40
The downward force is the block's weight = 60.2N
For the forces to balance
60.2+ F*0.6*sin40=Fcos40 => F = 60.2/(-0.6*sin40+cos40) = 158.266N To push the block up
That would be the force required to move the block up