The equivalent resistance of the circuit in
the figure is Req = 69.0 ohms.
l----------19ohms-------73ohms--l
l----73ohms------------19ohms--l
l-----R--------battery----switch---l
Find the value of R
Answer in units of ohms
the figure is Req = 69.0 ohms.
l----------19ohms-------73ohms--l
l----73ohms------------19ohms--l
l-----R--------battery----switch---l
Find the value of R
Answer in units of ohms
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Im assuming that R is internal resistance, with the 2 sections in series...
Req= (1/(19+73)+1/(19+73))^(-1/2)+R
Req-46=R
69-46=23
Req= (1/(19+73)+1/(19+73))^(-1/2)+R
Req-46=R
69-46=23
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Since the 19 and 73 ohm resistors in each string are in series you can just add them
We end up with an equivalent circuit with R in series with 2 parallel 92 ohm resistors
Any time you put 2 identical resistors in parallel the resistance is just 1/2 one of the resistors = 46 ohms.
So the equivalent circuit is now just R is in series with a 46 ohm resistor
The resistance in a series circuit just adds so:
Req = R + 46
R= 69-46= 23 ohms
We end up with an equivalent circuit with R in series with 2 parallel 92 ohm resistors
Any time you put 2 identical resistors in parallel the resistance is just 1/2 one of the resistors = 46 ohms.
So the equivalent circuit is now just R is in series with a 46 ohm resistor
The resistance in a series circuit just adds so:
Req = R + 46
R= 69-46= 23 ohms