A 9.0 ohm, a 7.0 ohm and an 18.0 ohm resistor are connected in series with a 12.0 V battery. Calculate the equivalent resistance. Answer in units of ohms.
What is the current in the circuit?
Answer in units of A.
What is the current in each resistor?
Answer in units of A.
What is the current in the circuit?
Answer in units of A.
What is the current in each resistor?
Answer in units of A.
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Total resistance is 34 ohms.
12 / 34 = .353A
Since it's in series, the same amount of current goes through all resistors, .353A.
You do realize that you're going to get tested on this, right? Better learn how to do it yourself.
Mike
12 / 34 = .353A
Since it's in series, the same amount of current goes through all resistors, .353A.
You do realize that you're going to get tested on this, right? Better learn how to do it yourself.
Mike
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To find the total resistance of resistors connected in SERIES, you just sum the resistances.
So,
the total resistance is 9 + 7 + 18 = 34 ohms
From Ohm's law we have
Voltage = current * total resistance
current = voltage / total resistance = 12 / 34 = 0.353 A
Since the resistors are connected in series, the same current must flow through all of them. So
current through each resistor = circuit current = 0.353 A
So,
the total resistance is 9 + 7 + 18 = 34 ohms
From Ohm's law we have
Voltage = current * total resistance
current = voltage / total resistance = 12 / 34 = 0.353 A
Since the resistors are connected in series, the same current must flow through all of them. So
current through each resistor = circuit current = 0.353 A