1 6x^2-24/x+2
a 6(x-2)
b 6(x+2)
c 3(x-8)
d 3(x+8)
2 3c+9/3c-9
a -1
b c+3/c-3
c c-3/c+3
d -3
3 k-2/k^2+2k-8
a 1/k-8
b 1/k+4
c 1/k+8
d 1/k-4
a 6(x-2)
b 6(x+2)
c 3(x-8)
d 3(x+8)
2 3c+9/3c-9
a -1
b c+3/c-3
c c-3/c+3
d -3
3 k-2/k^2+2k-8
a 1/k-8
b 1/k+4
c 1/k+8
d 1/k-4
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1. A
Solution:
(6x^2 -24)/ x+2 = (factor out the six on top portion and get:)
6(x^2 -4)/ x+2 = factor the x^2 - 4 and you get:)
6(x-2)(x+2)/ (x+2)= {(x+2) cancels out}=
6(x-2)= A
2. B
Solution:
(3c+9)/(3c-9) = (factor out the 3 from top and bottom factor and get:)
3(c+3)/3(c-3)= (the 3 cancels out from top and bottom and get:)
(c+3)/(c-3) = B
3. B
Solution:
(k-2)/(k^2 +2k-8)= (factor out the bottom portion and get:)
(k-2)/(k+4)(k-2)= (the k-2 cancels out from top and bottom and you end up with:)
1/(k+4)= B
Solution:
(6x^2 -24)/ x+2 = (factor out the six on top portion and get:)
6(x^2 -4)/ x+2 = factor the x^2 - 4 and you get:)
6(x-2)(x+2)/ (x+2)= {(x+2) cancels out}=
6(x-2)= A
2. B
Solution:
(3c+9)/(3c-9) = (factor out the 3 from top and bottom factor and get:)
3(c+3)/3(c-3)= (the 3 cancels out from top and bottom and get:)
(c+3)/(c-3) = B
3. B
Solution:
(k-2)/(k^2 +2k-8)= (factor out the bottom portion and get:)
(k-2)/(k+4)(k-2)= (the k-2 cancels out from top and bottom and you end up with:)
1/(k+4)= B
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dude u know if u press the Enter key; it leaves a space between ur part questions