A 320-g mass and a 400-g mass are attached to the two ends of a string that goes over a pulley
with a radius of 8.70 cm. Because of friction, the pulley does not begin to rotate. What is the
magnitude of the frictional torque on the bearing of the pulley if the system is in static equilibrium?
The answer is 0.0683 N m but im not sure how to get to it. I know i need to use torque but im not sure how. please show work thank you!!
with a radius of 8.70 cm. Because of friction, the pulley does not begin to rotate. What is the
magnitude of the frictional torque on the bearing of the pulley if the system is in static equilibrium?
The answer is 0.0683 N m but im not sure how to get to it. I know i need to use torque but im not sure how. please show work thank you!!
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Since equilibrium exists, the torque Q is the difference in the 2 applied torques:
Q = .400*.087*9.8 - .320*.087*9.8 = .0683 N∙m
Q = .400*.087*9.8 - .320*.087*9.8 = .0683 N∙m