In free fall, how fast is an object falling after 4 secs
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In free fall, how fast is an object falling after 4 secs

[From: ] [author: ] [Date: 11-05-03] [Hit: ]
8 m/s^2 times 4 seconds = 39.2 m/s.-9.8 m/4^2 =?......
On earth, the acceleration due to gravity is 9.8 m/s^2

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9.8 m/s^2 * 4 seconds = 39.2 m/s.

You can look at the units of measurement to see what you have to do to solve this:

The unit for acceleration is m/s^2 and this value is given.
You want to know what the velocity is (the speed) and the unit for this is m/s
So you have to get from m/s^2 to m/s and you can do this by multiplying m/s^2 (acceleration) by s (the unit of time) For example:

m/s^2 * s = m * s / s * s = m / s

In other words 9.8 m/s^2 times 4 seconds = 39.2 m/s.

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9.8 m/4^2 =?
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