Two blocks are released from the top of a building. One falls straight down while the other slides down a smooth ramp. If all friction is ignored, which one is moving faster when it reaches the bottom?
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They will both have the same speed at the bottom since the same amount of P.E. has been applied to their K.E. values.
V = √[2*g*h]
V = √[2*g*h]
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Assuming neither block sees any friction - their final speeds are each dependent only on the vertical release height by V = √2gh {where h = vertical release height}.
therefore both have the SAME speed at bottom ANS
therefore both have the SAME speed at bottom ANS