what is the inverse of
y=In(x-2)+1
and
y=log5(x-1)
it's log base 5
can you please show work
y=In(x-2)+1
and
y=log5(x-1)
it's log base 5
can you please show work
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to find the inverse x<--->y
x = ln(y-2)+1 --->ln(y-2) = x-1 --->y-2 = e^(x-1) or y = e^(x-1)+2
similar for question 2/
x = ln(y-2)+1 --->ln(y-2) = x-1 --->y-2 = e^(x-1) or y = e^(x-1)+2
similar for question 2/