Mg(OH)2(s) is only very slightly soluble in H2O.
Mg(OH)2(aq) + (NH4)2SO4(aq) ---> 2 H2O(l) +MgSO4(aq) + 2 NH3(aq)
NH3(aq) <=> NH3(g)
This is an acid-base reaction between NH4^+, an acid, and OH^-, a base coming from Mg(OH)2. The product are H2O and NH3, and NH3 is also part of an equilibrium as shown.
Hope this helps you understand. JIL HIR
Mg(OH)2(aq) + (NH4)2SO4(aq) ---> 2 H2O(l) +MgSO4(aq) + 2 NH3(aq)
NH3(aq) <=> NH3(g)
This is an acid-base reaction between NH4^+, an acid, and OH^-, a base coming from Mg(OH)2. The product are H2O and NH3, and NH3 is also part of an equilibrium as shown.
Hope this helps you understand. JIL HIR
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It would unrealistic to balance this equation when there isn't even an equal sign.
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You need to give us the products too.
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there should be an = somewhere...