10.0 cm^3 of solution of sulfuric acid contain 6.125g H2SO4.how many moles of h2so4 are present in 25 cm^3? what id the concentration of this solution in mole dm ^-3?
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Firstly work out how many moles are in 10cm^3 of the solution.
Moles = mass/relative molecular mass (Mr), considering the Mr of H2SO4 is 98g/mol and the solution contains 6.125g,
6.125/98 = 0.0625 moles per 10cm^3.
To find how many are present in 25cm^3, divide 0.0625 by 10 and multiply by 25 (find how many is is 1cm^3 then multiplying by 25) giving 0.15625 moles in 25cm^3
To find the concentration in mol dm^-3 divide moles by volume (remembering to convert to decimeters 1dm^3=1000cm^3) giving, 0.15625/ 0.025 = 6.25mol dm^-3
Moles = mass/relative molecular mass (Mr), considering the Mr of H2SO4 is 98g/mol and the solution contains 6.125g,
6.125/98 = 0.0625 moles per 10cm^3.
To find how many are present in 25cm^3, divide 0.0625 by 10 and multiply by 25 (find how many is is 1cm^3 then multiplying by 25) giving 0.15625 moles in 25cm^3
To find the concentration in mol dm^-3 divide moles by volume (remembering to convert to decimeters 1dm^3=1000cm^3) giving, 0.15625/ 0.025 = 6.25mol dm^-3