Hello. I got a question on my homework: A round closed pipe with radius R gets constant angular velocity clockwise(the pipe is horizontal) W1. A little particle with mass m can slip inside the pipe(the diameter is just bit Little than that of the pipe). We assume that there is no gravitation(g=0).
the friction coefficient between pipe and particle is K. We provide the particle an angular velocity W2 counter clockwise. The system is inertial.
The questions are: find the Normal and the friction on the particle.
The answers are: N=mR((W2)^2) and f=KmR(W2^2).
My question is: Why is the angular Velocity W1 not influences the friction?? Thanks
the friction coefficient between pipe and particle is K. We provide the particle an angular velocity W2 counter clockwise. The system is inertial.
The questions are: find the Normal and the friction on the particle.
The answers are: N=mR((W2)^2) and f=KmR(W2^2).
My question is: Why is the angular Velocity W1 not influences the friction?? Thanks
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the pipe is not accelerating......it is revolving with a constant velocity......
hence in the force equations the term of force due to pipe rotating just vanishes because we write relative to the pipe as a frame and the frame is non-accelerating..thus W1 is never used.
if the pipe is accelerating say with constant acceleration a1 then a pseudo force is exerted on the particle with respect to pipe as a frame. in that case, W1 turns up.
hope it helped!!
hence in the force equations the term of force due to pipe rotating just vanishes because we write relative to the pipe as a frame and the frame is non-accelerating..thus W1 is never used.
if the pipe is accelerating say with constant acceleration a1 then a pseudo force is exerted on the particle with respect to pipe as a frame. in that case, W1 turns up.
hope it helped!!