Integrate cos(x)/(1-x^2)

then find the integral from -1 to 1

Hi
Check your denominator (1-x^2)=(1-x)(1+x) The denom is zero at x-1 and x=-1 so the function does not exist at these points so it can't be evaluated from-1 to1.
Check the question.

The integral of that function looks horrific.
Another reason to check the question.

http://www.wolframalpha.com/input/?i=int…

Best wishes