the line that passes through point (-1,4) and point (6,y) has a slope of 5/7. find y
thanks in advance
thanks in advance
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y=mx+b
y=(5/7)x+b
4=-5/7+b = 28/7=-5/7+b
33/7=b
Therefore,
y=5/7(6)+33/7
y=30/7+33/7
y=63/7
y=9
y=(5/7)x+b
4=-5/7+b = 28/7=-5/7+b
33/7=b
Therefore,
y=5/7(6)+33/7
y=30/7+33/7
y=63/7
y=9
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x1 = - 1
y1 = 4
x2 = 6
y2 = y
m = 5/7
(y - y1) / (x2 - x1) = m
y - y1 = m(x2 - x1)
Subbing given values,
y - 4 = (5/7) [6 - (- 1)]
y - 4 = (5/7) (6 + 1)
y - 4 = (5/7) (7)
y - 4 = 35/7
y - 4 = 5
y = 5 + 4
y = 9
¯¯¯¯
y1 = 4
x2 = 6
y2 = y
m = 5/7
(y - y1) / (x2 - x1) = m
y - y1 = m(x2 - x1)
Subbing given values,
y - 4 = (5/7) [6 - (- 1)]
y - 4 = (5/7) (6 + 1)
y - 4 = (5/7) (7)
y - 4 = 35/7
y - 4 = 5
y = 5 + 4
y = 9
¯¯¯¯
-
m = 5/7
point (-1, 4)
(y - y1) = m(x - x1)
(y - 4) = (5/7)(x - (-1))
y - 4 = (5/7)x - 5/7
y = (5/7)x - 5/7 + 28/7
y = (5/7)x + 23/7
If x = 6:
y = (5/7)(6) + 23/7
y = 30/7 + 23/7 = 53/7 = 7 4/7
- .--
point (-1, 4)
(y - y1) = m(x - x1)
(y - 4) = (5/7)(x - (-1))
y - 4 = (5/7)x - 5/7
y = (5/7)x - 5/7 + 28/7
y = (5/7)x + 23/7
If x = 6:
y = (5/7)(6) + 23/7
y = 30/7 + 23/7 = 53/7 = 7 4/7
- .--
-
Point Slope:
y-y(1)=m(x-x(1))
y-4=5/7(x+1)
y-4=5/7x+5/7
+4 +4
y=5/7x + 33/7
y=5/7(6) + 33/7
y=9
y-y(1)=m(x-x(1))
y-4=5/7(x+1)
y-4=5/7x+5/7
+4 +4
y=5/7x + 33/7
y=5/7(6) + 33/7
y=9