Math cooridnates..........................................................

find the polar coordinates of the point with rectangular coordinates (-2, 3 sqrt 3).

answer choices
a. (4, pi/3)
b. (4, 2pi/3
c. (4, 5pi/6)
d. (2, 2pi/3)

e11q6

r = √((-2)^2 + (3√3)^2) = √(4 + 27) = √31
theta = arctan(3√3/(-2)) = 1.938 radians
(r, theta) = (√31, 1.938)

ez
r^2 = x^2 + y^2
r^2 = -2^2 + (3sqrt3)^2

x = rsin theta
y = rcos theta

SOLVE FROMT HERE BANANANANA