Let g(x) =(x-2)^2/x(x-2)
Give all x-values for which g is discontinuous?
Give all x-values for which g is discontinuous?
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Paul was correct about most points, except the canceling out. While it may not be what you're use to, you still get a hole discontinuity at these points. Try graphing the function and you should notice a little hole, even if it would be possible to simply cancel them out.4
It is also discontinuous at x = 2.
It is also discontinuous at x = 2.
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It's discontinuous for x values that make the denominator zero. HOWEVER: if you can cancel something out that's in the numerator and denominator, that doesn't count. So in this case you can simplify your equation to (x-2)/x. That means it's only discontinuous when x=0.